Question

fill in the missing parts for this table.

mass	volume	density (include units)
950 g	50 ml	b)____
2000 g	125 cm³	e)____
f)____	900 cm³	0.3 g/cm³
1250 g	25 ml	g)____
750 g	h)____	12 g/cm³
200 g	1000 cm³	i)____
1250 g	80 ml	j)____
700 g	k)____	2.5 g/cm³

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. Also, $1\ mL = 1\ cm^{3}$.

Step2: Calculate a)

Given $m = 250\ g$ and $V=80\ cm^{3}$, then $
ho=\frac{250\ g}{80\ cm^{3}}=3.125\ g/cm^{3}$.

Step3: Calculate b)

Given $m = 950\ g$ and $V = 50\ mL=50\ cm^{3}$, then $
ho=\frac{950\ g}{50\ cm^{3}} = 19\ g/cm^{3}$.

Step4: Calculate e)

Given $m = 2000\ g$ and $V=125\ cm^{3}$, then $
ho=\frac{2000\ g}{125\ cm^{3}}=16\ g/cm^{3}$.

Step5: Calculate f)

Given $
ho = 0.3\ g/cm^{3}$ and $V = 900\ cm^{3}$, using $m=
ho V$, we have $m=0.3\ g/cm^{3}\times900\ cm^{3}=270\ g$.

Step6: Calculate g)

Given $m = 1250\ g$ and $V = 25\ mL = 25\ cm^{3}$, then $
ho=\frac{1250\ g}{25\ cm^{3}}=50\ g/cm^{3}$.

Step7: Calculate h)

Given $m = 750\ g$ and $
ho=12\ g/cm^{3}$, using $V=\frac{m}{
ho}$, we get $V=\frac{750\ g}{12\ g/cm^{3}} = 62.5\ cm^{3}=62.5\ mL$.

Step8: Calculate i)

Given $m = 200\ g$ and $V = 1000\ cm^{3}$, then $
ho=\frac{200\ g}{1000\ cm^{3}}=0.2\ g/cm^{3}$.

Step9: Calculate j)

Given $m = 1250\ g$ and $V = 80\ mL=80\ cm^{3}$, then $
ho=\frac{1250\ g}{80\ cm^{3}}=15.625\ g/cm^{3}$.

Step10: Calculate k)

Given $m = 700\ g$ and $
ho=2.5\ g/cm^{3}$, using $V=\frac{m}{
ho}$, we have $V=\frac{700\ g}{2.5\ g/cm^{3}}=280\ cm^{3}=280\ mL$.

Answer:

a) $3.125\ g/cm^{3}$
b) $19\ g/cm^{3}$
e) $16\ g/cm^{3}$
f) $270\ g$
g) $50\ g/cm^{3}$
h) $62.5\ mL$
i) $0.2\ g/cm^{3}$
j) $15.625\ g/cm^{3}$
k) $280\ mL$