Question

find the indicated probability using the standard normal distribution. p(z > -0.715) p(z > -0.715)= (round to four decimal places as needed.)

Explanation:

Step1: Recall normal - distribution property

The total area under the standard - normal curve is 1, and $P(Z > z)=1 - P(Z\leq z)$.

Step2: Look up the value in the z - table

Looking up $z=-0.715$ in the standard normal distribution table (the cumulative - distribution function $\varPhi(z)$ gives $P(Z\leq z)$), we find that $P(Z\leq - 0.715)\approx0.2375$.

Step3: Calculate the required probability

Using the formula $P(Z > - 0.715)=1 - P(Z\leq - 0.715)$, we substitute the value from Step 2: $P(Z > - 0.715)=1 - 0.2375 = 0.7625$.

Answer:

$0.7625$