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1. find the standard deviation of the sample for the five states with t…

Question

  1. find the standard deviation of the sample for the five states with the most covered bridges:

oregon: 106
vermont: 121
indiana: 152
ohio: 234
pennsylvania: 347
round to the nearest tenth. (one decimal)

Explanation:

Step1: Calculate the mean ($\bar{x}$)

First, find the sum of the data values: \(106 + 121 + 152 + 224 + 347 = 950\)
There are \(n = 5\) data points, so the mean is \(\bar{x}=\frac{950}{5}=190\)

Step2: Calculate the squared differences from the mean

For each data point \(x_i\), calculate \((x_i - \bar{x})^2\):

  • For \(106\): \((106 - 190)^2=(-84)^2 = 7056\)
  • For \(121\): \((121 - 190)^2=(-69)^2 = 4761\)
  • For \(152\): \((152 - 190)^2=(-38)^2 = 1444\)
  • For \(224\): \((224 - 190)^2=(34)^2 = 1156\)
  • For \(347\): \((347 - 190)^2=(157)^2 = 24649\)

Step3: Calculate the sum of squared differences

Sum these squared differences: \(7056+4761 + 1444+1156+24649 = 39066\)

Step4: Calculate the sample variance ($s^2$)

The sample variance is \(\frac{\sum(x_i - \bar{x})^2}{n - 1}\), so \(s^2=\frac{39066}{5 - 1}=\frac{39066}{4}=9766.5\)

Step5: Calculate the sample standard deviation ($s$)

Take the square root of the variance: \(s=\sqrt{9766.5}\approx98.8\)

Answer:

\(98.8\)