Question

four different objects are placed on a number line at 0. the chart describes the motion of each object. object motion w 3 units left, then 3 units right x 6 units right, then 18 units right y 8 units left, then 24 units right z 16 units right, then 8 units left using the information in the chart, the distance and displacement of each object can be determined. which object has a distance that is three times as great as its displacement? o w o x o y o z

Explanation:

Step1: Recall distance and displacement formulas

Distance is total path length, displacement is final - initial position.

Step2: Calculate for Object W

Distance: $| - 3|+3=3 + 3=6$. Displacement: $-3 + 3=0$. Ratio of distance to displacement is undefined (since displacement is 0).

Step3: Calculate for Object X

Distance: $6+18 = 24$. Displacement: $6 + 18=24$. Ratio of distance to displacement is $\frac{24}{24}=1$.

Step4: Calculate for Object Y

Distance: $| - 8|+24=8 + 24=32$. Displacement: $-8 + 24 = 16$. Ratio of distance to displacement is $\frac{32}{16}=2$.

Step5: Calculate for Object Z

Distance: $16+| - 8|=16 + 8=24$. Displacement: $16-8 = 8$. Ratio of distance to displacement is $\frac{24}{8}=3$.

Answer:

Z