Question

give the complete electron configuration for the two gallium ions. do not use the noble gas abbreviation. the oxidation numbers from many, but not all, periodic tables are 1 and 3. one ion completely empties the 4s orbital. use 4s^0 to hold the place for the empty subshell. ga^+1 has 1 electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 2 3 4 ga^+3 has 5 electrons, and the electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 6 7 8 a. 10 b. 12 c. 14 d. 16 e. 18 f. 30 g. 31 h. 28 i. 26 j. 3p^6 k. 3p^4 l. 3s^2 m. 3d^10 n. 4d^1 o. 4s^2 p. 4p^6 q. 5s^2 r. 4p^0 s. 4s^0 t. 4d^3 u. 4p^1 v. 3p^5

Explanation:

Step1: Determine number of electrons in Ga+1

Gallium (Ga) has 31 electrons. Ga+1 has lost 1 electron, so it has 30 electrons.

Step2: Write electron - configuration for Ga+1

After 1s²2s²2p⁶3s²3p⁶, the next sub - shells are 3d¹⁰4s⁰4p⁰.

Step3: Determine number of electrons in Ga+3

Ga+3 has lost 3 electrons. So it has 28 electrons.

Step4: Write electron - configuration for Ga+3

After 1s²2s²2p⁶3s²3p⁶, the next sub - shells are 3d¹⁰4s⁰4p⁰.

Answer:

1. F. 30
2. M. 3d¹⁰
3. S. 4s⁰
4. R. 4p⁰
5. H. 28
6. M. 3d¹⁰
7. S. 4s⁰
8. R. 4p⁰