Question

given that 0.107 mol br2 was consumed, calculate the amount (mol) brcl formed.

Explanation:

Step1: Determine the mole - ratio

Assume the reaction is $Br_2 + Cl_2
ightarrow2BrCl$. The mole - ratio of $Br_2$ to $BrCl$ is 1:2.

Step2: Calculate the moles of $BrCl$

Using the mole - ratio, if $n(Br_2)=0.107$ mol, then $n(BrCl) = 2\times n(Br_2)$. So $n(BrCl)=2\times0.107$ mol.
$n(BrCl) = 0.214$ mol

Answer:

0.214