Question

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7 4 grams of hydrogen and 32 grams of oxygen will combine to form: a 36 grams of water b 28 grams of hydroxide c 32 grams of oxygen d 36 grams of deuterium

Explanation:

Step1: Write chemical reaction

The chemical reaction for hydrogen and oxygen combining to form water is \(2H_2 + O_2=2H_2O\). The molar mass of \(H_2\) is approximately \(2\ g/mol\), so \(4\ g\) of \(H_2\) is \(n_{H_2}=\frac{4\ g}{2\ g/mol} = 2\ mol\). The molar mass of \(O_2\) is approximately \(32\ g/mol\), so \(32\ g\) of \(O_2\) is \(n_{O_2}=\frac{32\ g}{32\ g/mol}=1\ mol\).

Step2: Determine product amount by stoichiometry

From the balanced - equation, \(2\ mol\) of \(H_2\) reacts with \(1\ mol\) of \(O_2\) to form \(2\ mol\) of \(H_2O\). The molar mass of \(H_2O\) is \(M = 18\ g/mol\), and the mass of \(2\ mol\) of \(H_2O\) is \(m = 2\ mol\times18\ g/mol=36\ g\). Also, hydrogen and oxygen do not form hydroxide or deuterium in this reaction, and oxygen is a reactant not the product in the context of this combination reaction.

Answer:

A. 36 grams of water