Question

graphite | h₂o, h⁺, o₂, cd²⁺ | cd δg° = +629 kj is the reaction thermodynamically favorable or unfavorable? 1. favorable 2. unfavorable enter the answer choice number.

Explanation:

To determine if a reaction is thermodynamically favorable, we use the standard Gibbs free energy change ($\Delta G^\circ$). A reaction is favorable (spontaneous) when $\Delta G^\circ < 0$ (negative) and unfavorable (non - spontaneous) when $\Delta G^\circ>0$ (positive). Here, $\Delta G^\circ = + 629\space kJ$, which is positive. So the reaction is thermodynamically unfavorable.

Answer:

1. unfavorable