Question

group a
trial 1: 11.1 ml, trial 2: 12.4 ml, trial 3: 21.0 ml, trial 4: 16.0 ml
group b:
trial 1: 16.8 ml, trial 2: 17.3 ml, trial 3: 17.0 ml, trial 4: 17.2 ml

1. if the actual volume of the object is 15.2 ml, which set of data is more accurate? why?

Explanation:

1. First, calculate the average for Group A:

• Trials: 11.1 mL, 12.4 mL, 21.0 mL, 16.0 mL.
• Sum: \(11.1 + 12.4 + 21.0 + 16.0 = 60.5\) mL.
• Average: \(\frac{60.5}{4}=15.125\approx15.1\) mL.

1. Calculate the average for Group B:

• Trials: 16.8 mL, 17.3 mL, 17.0 mL, 17.2 mL.
• Sum: \(16.8 + 17.3 + 17.0 + 17.2 = 68.3\) mL.
• Average: \(\frac{68.3}{4}=17.075\approx17.1\) mL.

1. Compare the averages to the actual volume (15.2 mL):

• The average of Group A (≈15.1 mL) is closer to 15.2 mL than the average of Group B (≈17.1 mL). Accuracy refers to how close a measurement (or average of measurements) is to the true value, so Group A's data is more accurate.

Answer:

Group A's data is more accurate (assuming the fourth trial of Group A is 16.0 mL as per the table).