Question

the height of a model rocket is 4.5% of the height of the actual rocket. the model is 1.32 m high. how high is the actual rocket?

Explanation:

Step1: Define variables and relationship

Let $H$ = actual rocket height. The model height is 4.5% of $H$, so:
$1.32 = 0.045 \times H$

Step2: Solve for actual height

Rearrange to isolate $H$:
$H = \frac{1.32}{0.045}$

Step3: Calculate the value

Perform the division:
$H = \frac{1320}{45} = \frac{88}{3} \approx 29.33$

Answer:

The actual rocket is $\frac{88}{3}$ m (or approximately 29.33 m) high.