QUESTION IMAGE
Question
heights, in inches, for the 200 graduating seniors from washington high school are summarized in the frequency table below.
| height | frequency |
|---|---|
| 60 inches ≤ height < 66 inches | 84 |
| 66 inches ≤ height < 72 inches | 62 |
| 72 inches ≤ height < 78 inches | 24 |
| height ≥ 78 inches | 8 |
which of the following statements about the median height is true?
a it is greater than or equal to 78 inches.
b it is greater than or equal to 72 inches but less than 78 inches.
c it is greater than or equal to 66 inches but less than 72 inches.
d it is greater than or equal to 60 inches but less than 66 inches.
e it is less than 60 inches.
Step1: Calculate cumulative frequencies
| Height | Frequency | Cumulative Frequency |
|---|---|---|
| 60 inches ≤ height < 66 inches | 84 | 22 + 84=106 |
| 66 inches ≤ height < 72 inches | 62 | 106+62 = 168 |
| 72 inches ≤ height < 78 inches | 24 | 168+24 = 192 |
| Height ≥ 78 inches | 8 | 192 + 8=200 |
Step2: Determine position of median
There are \(n = 200\) data - points. For a set of \(n\) data - points (where \(n\) is even), the median is the average of the \(\frac{n}{2}\)th and \((\frac{n}{2}+1)\)th ordered data - points. Here, \(\frac{n}{2}=\frac{200}{2}=100\) and \(\frac{n}{2}+1 = 101\).
Step3: Locate median class
The 100th and 101st ordered data - points fall within the class "60 inches ≤ height < 66 inches" since the cumulative frequency up to the class "60 inches ≤ height < 66 inches" is 106 which includes the 100th and 101st values.
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D. It is greater than or equal to 60 inches but less than 66 inches.