Question

a hot air balloon holds 4,328 cubic meters of helium. the density of helium is 0.1785 kilograms per cubic meter. how many kilograms of helium does the balloon contain, rounded to the nearest tenth of a kilogram? 3,747.9 kg 3,875.3 kg 772.5 kg 4,383.2 kg

Explanation:

Step1: Recall density - mass - volume formula

The formula is $\text{Mass}=\text{Density}\times\text{Volume}$.

Step2: Substitute given values

We have $\text{Density} = 0.1785$ kg/m³ and $\text{Volume}=4328$ m³. So, $\text{Mass}=0.1785\times4328$.

Step3: Calculate the product

$0.1785\times4328 = 772.548$ kg.

Step4: Round to nearest tenth

Rounding $772.548$ to the nearest tenth gives $772.5$ kg.

Answer:

772.5 kg