Question

how many grams of neon, ne, would contain the same number of atoms as 207.2 g of lead, pb? mass: g

Explanation:

Step1: Calculate moles of lead

The molar mass of lead ($Pb$) is $207.2\ g/mol$. Using the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass and $M$ is the molar mass. For lead, $n_{Pb}=\frac{207.2\ g}{207.2\ g/mol}=1\ mol$.

Step2: Determine moles of neon

According to Avogadro's number, equal - number of moles of different substances contain the same number of atoms. So, the number of moles of neon ($Ne$) is also $n_{Ne} = 1\ mol$ since the number of atoms of neon is the same as that of lead.

Step3: Calculate mass of neon

The molar mass of neon is $M_{Ne}=20.18\ g/mol$. Using the formula $m = n\times M$, for neon, $m_{Ne}=n_{Ne}\times M_{Ne}=1\ mol\times20.18\ g/mol = 20.18\ g$.

Answer:

$20.18$