Question

1. how many moles are in 9.50 x 10^{25} atoms of copper?

Explanation:

Step1: Recall Avogadro's number

Avogadro's number ($N_A$) is $6.022\times 10^{23}$ atoms/mol.

Step2: Use the formula for moles

The formula to find the number of moles ($n$) is $n=\frac{N}{N_A}$, where $N$ is the number of atoms. Here $N = 9.50\times 10^{25}$ atoms. So $n=\frac{9.50\times 10^{25}\text{ atoms}}{6.022\times 10^{23}\text{ atoms/mol}}$.

Step3: Calculate the result

$n=\frac{9.50\times 10^{25}}{6.022\times 10^{23}}\text{ mol}\approx158\text{ mol}$

Answer:

$158$ mol