Question

how many moles of pcl₅ are present in a 100.0 g sample? select the correct answer below: 0.12 0.24 0.48 0.96

Explanation:

Step1: Find molar mass of PCl₅

The molar mass of P (phosphorus) is approximately 30.97 g/mol and Cl (chlorine) is approximately 35.45 g/mol. For PCl₅, molar mass $M = 30.97+5\times35.45=30.97 + 177.25=208.22$ g/mol.

Step2: Calculate moles

Use the formula $n=\frac{m}{M}$, where $m = 100.0$ g and $M = 208.22$ g/mol. So $n=\frac{100.0}{208.22}\approx0.48$ mol.

Answer:

C. 0.48