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instructions: balance the chemical equations below. 1) ___ n₂ + ___ o₂ …

Question

instructions: balance the chemical equations below.

  1. _ n₂ + _ o₂ → ___ n₂o
  2. _ zn + _ hcl → _ zncl₂ + _ h₂
  3. _ fe + _ o₂ → ___ fe₂o₃
  4. _ al + _ feo → _ al₂o₃ + _ fe
  5. _ p₄ + _ o₂ → ___ p₂o₅
  6. _ c₃h₈ + _ o₂ → _ co₂ + _ h₂o
  7. _ mgf₂ + _ li₂co₃ → _ mgco₃ + _ lif
  8. _ br₂ + _ h₂o → _ hbr + _ o₂
  9. _ kbr + _ h₂so₄ → _ k₂so₄ + _ hbr
  10. _ c + _ so₂ → _ cs₂ + _ co
  11. _ al + _ h₂so₄ → _ al₂(so₄)₃ + _ h₂
  12. _ fecl₃ + _ naoh → _ fe(oh)₃ + _ nacl

Explanation:

Step1: Balance nitrogen and oxygen in $N_2 + O_2

ightarrow N_2O$
By trial - and - error, we get $2N_2+O_2 = 2N_2O$

Step2: Balance zinc and hydrogen - chlorine in $Zn + HCl

ightarrow ZnCl_2 + H_2$
We need 2 moles of $HCl$, so $Zn + 2HCl=ZnCl_2 + H_2$

Step3: Balance iron and oxygen in $Fe + O_2

ightarrow Fe_2O_3$
Multiply to get $4Fe + 3O_2 = 2Fe_2O_3$

Step4: Balance aluminum, iron and oxygen in $Al + FeO

ightarrow Al_2O_3 + Fe$
We get $2Al+3FeO = Al_2O_3 + 3Fe$

Step5: Balance phosphorus and oxygen in $P_4 + O_2

ightarrow P_2O_5$
We have $P_4+5O_2 = 2P_2O_5$

Step6: Balance carbon, hydrogen and oxygen in $C_3H_8 + O_2

ightarrow CO_2 + H_2O$
We get $C_3H_8+5O_2 = 3CO_2 + 4H_2O$

Step7: Balance magnesium, fluorine, lithium and carbon - oxygen in $MgF_2 + Li_2CO_3

ightarrow MgCO_3 + LiF$
We have $MgF_2+Li_2CO_3 = MgCO_3 + 2LiF$

Step8: Balance bromine, hydrogen and oxygen in $Br_2 + H_2O

ightarrow HBr + O_2$
We get $2Br_2 + 2H_2O = 4HBr+O_2$

Step9: Balance potassium, bromine, hydrogen and sulfur - oxygen in $KBr + H_2SO_4

ightarrow K_2SO_4 + HBr$
We have $2KBr + H_2SO_4 = K_2SO_4+2HBr$

Step10: Balance carbon and sulfur - oxygen in $C + SO_2

ightarrow CS_2 + CO$
We get $5C + 2SO_2 = CS_2+4CO$

Step11: Balance aluminum, hydrogen and sulfur - oxygen in $Al + H_2SO_4

ightarrow Al_2(SO_4)_3 + H_2$
We have $2Al + 3H_2SO_4 = Al_2(SO_4)_3+3H_2$

Step12: Balance iron, chlorine, sodium and hydrogen - oxygen in $FeCl_3 + NaOH

ightarrow Fe(OH)_3 + NaCl$
We have $FeCl_3 + 3NaOH = Fe(OH)_3+3NaCl$

Answer:

  1. $2N_2+O_2 = 2N_2O$
  2. $Zn + 2HCl=ZnCl_2 + H_2$
  3. $4Fe + 3O_2 = 2Fe_2O_3$
  4. $2Al+3FeO = Al_2O_3 + 3Fe$
  5. $P_4+5O_2 = 2P_2O_5$
  6. $C_3H_8+5O_2 = 3CO_2 + 4H_2O$
  7. $MgF_2+Li_2CO_3 = MgCO_3 + 2LiF$
  8. $2Br_2 + 2H_2O = 4HBr+O_2$
  9. $2KBr + H_2SO_4 = K_2SO_4+2HBr$
  10. $5C + 2SO_2 = CS_2+4CO$
  11. $2Al + 3H_2SO_4 = Al_2(SO_4)_3+3H_2$
  12. $FeCl_3 + 3NaOH = Fe(OH)_3+3NaCl$