QUESTION IMAGE
Question
interpreting kinematics graphs
answer the questions 1 - 10 based on the graph of a remote - controlled car below. directions should be indicated as positive or negative signs on numerical values or, if specifically asked for direction, written as the words positive or negative.
- what does the slope of the line in the graph above represent?
- describe the motion of the remote - controlled car, including the direction, from t = 0 s to t = 4 s.
- what is the velocity of the car at t = 9 s?
- what is the direction (positive and/or negative) that the car is going at t = 9 s?
- describe the direction of motion of the car at t = 11 s.
- describe the motion of the car, including direction, from t = 12 s to t = 18 s.
- what is the velocity of the car at t = 15 s?
- what is the acceleration of the car at t = 15 s?
- what is the velocity of the car at t = 18.5 s?
- what is the total displacement of the car for the entire 20 - second period of time?
1.
Step1: Recall kinematics - slope concept
In a velocity - time graph, the slope represents acceleration. In a position - time graph, the slope represents velocity. Since the problem is about kinematics of a car and the slope of the line in a kinematics graph is being asked, if it is a velocity - time graph, slope = $\frac{\Delta v}{\Delta t}$ which is acceleration.
Step1: Analyze time interval
From $t = 0$s to $t=4$s, if the graph is a position - time graph and the slope is positive, the car is moving in the positive direction with a constant velocity (if the slope is constant). If it is a velocity - time graph and the value of velocity is positive, the car is moving in the positive direction and if the slope of the velocity - time graph is positive, it is accelerating in the positive direction.
Step1: Locate $t = 9$s on the graph
Find the value of the y - axis (velocity if it is a velocity - time graph) corresponding to $t = 9$s on the graph.
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Acceleration
2.