Question

an ionic compound is named tin (ii) phosphide. complete the table to determine the number of ions of each element in one formula unit of the compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign. in one formula unit what is the formula for the ionic compound? element: tin (ii), phosphorus charge of one ion total charge of ion(s) in compound number of ion(s) in compound*

Explanation:

Step1: Determine ion charges

Tin (II) ion: $\text{Sn}^{2+}$ (charge = +2). Phosphide ion: $\text{P}^{3-}$ (charge = -3).

Step2: Balance total charges

Let number of $\text{Sn}^{2+}$ be $x$, $\text{P}^{3-}$ be $y$. Total positive charge: $2x$, total negative charge: $3y$. For neutral compound, $2x = 3y$. Smallest integers: $x = 3$, $y = 2$.

Step3: Write formula

Combine ions: $\text{Sn}_3\text{P}_2$.

Answer:

$\text{Sn}_3\text{P}_2$

Table Completion:

Element	Charge of One Ion	Total Charge of Ion(s) in Compound	Number of Ion(s) in Compound
Phosphorus	$-3$	$-6$ (2 ions: $2\times(-3)$)	$2$