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isabelles family held a garage sale last weekend. they sold 7 items for…

Question

isabelles family held a garage sale last weekend. they sold 7 items for: $8.00 $8.00 $5.00 $2.00 $4.00 $3.00 $5.00 what was the mean absolute deviation of the prices of the items? if the answer is a decimal, round it to the nearest ten cents. mean absolute deviation (mad): $

Explanation:

Step1: Calculate the mean

The sum of the prices is \(8 + 8+5 + 2+4 + 3+5=35\). There are \(n = 7\) items. The mean \(\bar{x}=\frac{35}{7}=5\).

Step2: Calculate the absolute - deviations

For \(8\): \(|8 - 5|=3\) (twice); for \(5\): \(|5 - 5| = 0\) (twice); for \(2\): \(|2 - 5|=3\); for \(4\): \(|4 - 5| = 1\); for \(3\): \(|3 - 5|=2\).

Step3: Calculate the sum of absolute - deviations

The sum of absolute - deviations is \(3\times2+0\times2 + 3+1+2=6 + 0+3 + 1+2 = 12\).

Step4: Calculate the mean absolute deviation

The mean absolute deviation \(MAD=\frac{12}{7}\approx1.71\). Rounding to the nearest ten - cents, \(MAD = 1.70\).

Answer:

\(1.70\)