Question

a jar contains 11 green marbles, 6 red marbles, and 9 blue marbles. a marble is selected at random, not replaced, and then a second marble is selected. what is the probability of selecting a red marble followed by a green marble?
a. 33/325
b. 33/338
c. 224/351
d. 65/649

Explanation:

Step1: Calculate total number of marbles

$11 + 6+9=26$

Step2: Calculate probability of first - selecting a red marble

The probability of selecting a red marble first is $\frac{6}{26}$ since there are 6 red marbles out of 26 total marbles.

Step3: Calculate probability of second - selecting a green marble

After one red marble is selected and not replaced, there are 25 marbles left. The probability of selecting a green marble second is $\frac{11}{25}$ since there are 11 green marbles left.

Step4: Calculate combined probability

The probability of both events happening (red then green) is the product of their individual probabilities. So $P=\frac{6}{26}\times\frac{11}{25}=\frac{6\times11}{26\times25}=\frac{66}{650}=\frac{33}{325}$

Answer:

A. 33/325