Question

jeremy will roll a number cube, numbered 1 - 6, twice. what is the probability of rolling an even number, then the number 3?

Explanation:

Step1: Calculate probability of rolling an even number

The even numbers on a 1 - 6 number cube are 2, 4, 6. So there are 3 even numbers out of 6 total numbers. The probability of rolling an even number on the first roll, $P(\text{even})=\frac{3}{6}=\frac{1}{2}$.

Step2: Calculate probability of rolling a 3

There is 1 number 3 on a 1 - 6 number cube. So the probability of rolling a 3 on the second roll, $P(3)=\frac{1}{6}$.

Step3: Use multiplication rule for independent events

Since the two rolls are independent events, the probability of both events occurring is the product of their individual probabilities. So $P = P(\text{even})\times P(3)=\frac{1}{2}\times\frac{1}{6}=\frac{1}{12}$.

Answer:

A. $\frac{1}{12}$