QUESTION IMAGE
Question
journal
compare the graph of a ratio relationship with the graph of a relationship that is not represented by a ratio. how are they similar and different? use an example to explain.
remember
you can represent equivalent ratios on a coordinate plane. the ratio \\(\frac{y}{x}\\) is plotted as the ordered pair \\((x, y)\\). the points that represent the equivalent ratios form a straight line that passes through the origin.
practice
create a graph to represent the values shown in each ratio table.
1
| weight (pounds) | 1 | 2 | 4 | 5 |
|---|
(a) what is the cost for a weight of 3 pounds?
(b) what is the weight for a cost of $21?
2
| time (hours) | 1 | 3 | 5 | 7 |
|---|
(a) what is the distance at 6 hours?
(b) what is the time at 275 miles?
Problem 1
Part (a)
Step1: Find the rate of cost per pound
From the table, when weight \( x = 1 \) pound, cost \( y = 3 \) dollars. So the rate is \( \frac{y}{x}=\frac{3}{1} = 3 \) dollars per pound.
Step2: Calculate cost for 3 pounds
Using the rate, for \( x = 3 \) pounds, cost \( y=3\times3 = 9 \) dollars.
Step1: Find the rate of cost per pound (same as before, 3 dollars per pound)
Step2: Calculate weight for $21 cost
Let weight be \( x \). We know \( y = 3x \). For \( y = 21 \), solve \( 21=3x \), so \( x=\frac{21}{3}=7 \) pounds.
Step1: Find the rate of distance per hour
From the table, when time \( x = 1 \) hour, distance \( y = 25 \) miles. So the rate is \( \frac{y}{x}=\frac{25}{1}=25 \) miles per hour.
Step2: Calculate distance at 6 hours
Using the rate, for \( x = 6 \) hours, distance \( y = 25\times6=150 \) miles.
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The cost for a weight of 3 pounds is 9 dollars.