Question

1. a 5.4 kg ball is dropped from a cliff, and it accelerates downward due to the force of gravity. a. what is the balls downward velocity after 3 seconds of free - fall? assuming we ignore air resistance.

Explanation:

Step1: Identify the acceleration

The acceleration due to gravity $g = 9.8\ m/s^{2}$ (near - Earth's surface).

Step2: Use the velocity - time formula

The formula for velocity in free - fall with initial velocity $u = 0$ (dropped) is $v=u + gt$. Here, $u = 0$, $g = 9.8\ m/s^{2}$, and $t = 3\ s$. So $v=0+9.8\times3$.

Step3: Calculate the velocity

$v = 9.8\times3=29.4\ m/s$.

Answer:

$29.4\ m/s$