Question

1. a 6.0 kg cart accelerates at 2.5 m/s². calculate the net force on the cart. step 1: step 2: step 3: 6. a net force of 45 n causes an object to accelerate at 3.0 m/s². what is the objects mass? step 1: step 2: step 3: 7. an object of mass 10 kg experiences a net force of 30 n. what is its acceleration? step 1: step 2: step 3:

Explanation:

Step1: Identify the formula

We use Newton's second - law formula $F = ma$, where $F$ is the net force, $m$ is the mass, and $a$ is the acceleration.

Step2: Solve for the unknown variable in each problem

Problem 5

Given $m = 6.0\ kg$ and $a=2.5\ m/s^{2}$. Substitute into $F = ma$.
$F=(6.0\ kg)\times(2.5\ m/s^{2})$

Problem 6

Given $F = 45\ N$ and $a = 3.0\ m/s^{2}$. Solve for $m$ from $F = ma$, so $m=\frac{F}{a}$.
$m=\frac{45\ N}{3.0\ m/s^{2}}$

Problem 7

Given $m = 10\ kg$ and $F = 30\ N$. Solve for $a$ from $F = ma$, so $a=\frac{F}{m}$.
$a=\frac{30\ N}{10\ kg}$

Step3: Calculate the results

Problem 5

$F=(6.0)\times(2.5)=15\ N$

Problem 6

$m=\frac{45}{3.0}=15\ kg$

Problem 7

$a=\frac{30}{10}=3\ m/s^{2}$

Answer:

1. $15\ N$
2. $15\ kg$
3. $3\ m/s^{2}$