Question

lakewood is a growing industrial town. every year, the level of co2 emissions from the town increases by 12%. if the town produced 206,260 metric tons of co2 this year, how much will be produced 8 years in the future? if necessary, round your answer to the nearest whole number. metric tons submit

Explanation:

Step1: Identify the formula for exponential growth

The formula for exponential growth is $A = P(1 + r)^t$, where $A$ is the final amount, $P$ is the initial amount, $r$ is the annual growth rate (as a decimal), and $t$ is the time in years.

Step2: Identify the values of P, r, and t

Here, $P = 206260$ metric tons, $r = 0.12$ (since 12% = 0.12), and $t = 8$ years.

Step3: Substitute the values into the formula

Substitute the values into the formula: $A = 206260(1 + 0.12)^8$.
First, calculate $(1 + 0.12)^8$. $1.12^8 \approx 2.475963176$.
Then, multiply by the initial amount: $A = 206260 \times 2.475963176 \approx 206260 \times 2.475963176$.
Calculate $206260 \times 2.475963176 \approx 510792$.

Answer:

510792