Question

look at the equation below.
o2 + cs2 → co2 + so2
which of the following shows the equation balanced?
a. o2 + cs2 → co2 + so2
b. 4 o2 + 4 cs2 → 4 co2 + 4 so2
c. 3 o2 + cs2 → 2 co2 + so2
d. 3 o2 + cs2 → co2 + 2 so2

Explanation:

Step1: Count atoms on reactant side

On the left - hand side of the unbalanced equation $O_2 + CS_2
ightarrow CO_2+SO_2$, we have 1 carbon (C) atom, 2 sulfur (S) atoms and 2 oxygen (O) atoms.

Step2: Analyze option A

In $O_2 + CS_2
ightarrow CO_2+SO_2$, on the right - hand side, we have 1 C, 1 S and 4 O atoms. The S and O atoms are not balanced.

Step3: Analyze option B

In $4O_2 + 4CS_2
ightarrow 4CO_2+4SO_2$, on the left - hand side we have 4 C, 8 S and 8 O atoms, and on the right - hand side we have 4 C, 4 S and 16 O atoms. The S and O atoms are not balanced.

Step4: Analyze option C

In $3O_2 + CS_2
ightarrow 2CO_2+SO_2$, on the left - hand side we have 1 C, 2 S and 6 O atoms, and on the right - hand side we have 2 C, 1 S and 6 O atoms. The C and S atoms are not balanced.

Step5: Analyze option D

In $3O_2 + CS_2
ightarrow CO_2+2SO_2$, on the left - hand side: C = 1, S = 2, O=6. On the right - hand side: C = 1, S = 2, O = 2 + 2×2=6. The equation is balanced.

Answer:

D. $3O_2 + CS_2
ightarrow CO_2+2SO_2$