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do males or females feel more tense or stressed out at work? a survey o…

Question

do males or females feel more tense or stressed out at work? a survey of employed adults conducted online by a company on behalf of a research organization revealed the data in the contingency table shown to the right. complete parts (a) through (d) below.

gender
yes305315620
no200100300
total505415920

a. what is the probability that a randomly selected person’s gender is female? 0.451 (type an integer or a decimal. round to three decimal places as needed.)
b. what is the probability that a randomly selected person feels tense or stressed out at work and is female? 0.342 (type an integer or a decimal. round to three decimal places as needed.)
c. what is the probability that a randomly selected person feels tense or stressed out at work or is female? (type an integer or a decimal. round to three decimal places as needed.)

Explanation:

Response
Part (a)

Step1: Find total number of people

Total number of people is the sum of all totals, which is \(505 + 415 = 920\) (or from the "Total" row, it's 920).

Step2: Find number of females

Number of females is 415 (from the "Female" column total).

Step3: Calculate probability

Probability \(P(\text{Female})=\frac{\text{Number of Females}}{\text{Total Number of People}}=\frac{415}{920}\approx0.451\)

Step1: Find number of females who felt tense or stressed

From the table, females who felt tense or stressed (Yes) is 315.

Step2: Total number of people is 920.

Step3: Calculate probability

Probability \(P(\text{Yes and Female})=\frac{\text{Number of Females who said Yes}}{\text{Total Number of People}}=\frac{315}{920}\approx0.342\)

Step1: Use the formula for probability of union: \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\)

Let \(A\) be "feels tense or stressed" and \(B\) be "female".

Step2: Find \(P(A)\), \(P(B)\), \(P(A\cap B)\)

  • \(P(A)=\frac{620}{920}\) (number of people who said Yes is 620)
  • \(P(B)=\frac{415}{920}\) (number of females is 415)
  • \(P(A\cap B)=\frac{315}{920}\) (number of females who said Yes is 315)

Step3: Calculate \(P(A\cup B)\)

\(P(A\cup B)=\frac{620 + 415 - 315}{920}=\frac{720}{920}\approx0.783\)

Answer:

\(0.451\)

Part (b)