Question

manganese (mn) is element 25 on the periodic table. a sample contains 9.09x10^22 atoms of mn. calculate the amount of mn. mol mn

Explanation:

Step1: Recall Avogadro's number

Avogadro's number ($N_A$) is $6.022\times 10^{23}$ atoms/mol.

Step2: Use the formula for moles

The formula to convert number of atoms ($N$) to moles ($n$) is $n=\frac{N}{N_A}$. Given $N = 9.09\times 10^{22}$ atoms of Mn. Then $n=\frac{9.09\times 10^{22}\text{ atoms}}{6.022\times 10^{23}\text{ atoms/mol}}$.

Step3: Calculate the number of moles

$n=\frac{9.09\times 10^{22}}{6.022\times 10^{23}}=\frac{9.09}{6.022}\times10^{22 - 23}\approx1.51\times10^{- 1}\text{ mol}$.

Answer:

$0.151$ mol Mn