QUESTION IMAGE
Question
- maria and don papace are flying to florida to explore the possibility of moving there. they will be traveling with their two teenage sons. the table below lists information they have researched on the round - trip airfares that are available for purchase on the dates they have chosen to travel. use the table to determine the missing values a - g.
| round - trip airfare chicago to orlando 2 adults, 2 children | frequency | relative frequency | cumulative frequency | relative cumulative frequency |
|---|---|---|---|---|
| $251 | 2 | 0.025 | 6 | 0.075 |
| $299 | 3 | b | 9 | 0.113 |
| $305 | 12 | 0.150 | 21 | 0.263 |
| $353 | 7 | 0.088 | d | 0.350 |
| $379 | 2 | 0.025 | 30 | 0.375 |
| $413 | 4 | 0.050 | 34 | f |
| $457 | 20 | c | 54 | 0.675 |
| $495 | 5 | 0.063 | 59 | 0.738 |
| $505 | 7 | 0.088 | e | 0.825 |
| $509 | 2 | 0.025 | 68 | 0.850 |
| $513 | 12 | 0.150 | 80 | g |
| $565 | a | |||
| total |
Step1: Find total frequency
Since relative frequency = frequency / total frequency, and for the first row relative frequency of $0.050$ with frequency $4$, total frequency $n=\frac{4}{0.050}=80$. So $a = 80$.
Step2: Calculate $b$
For the third - row with frequency $3$, relative frequency $b=\frac{3}{80}=0.038$.
Step3: Calculate $c$
For the row with airfare $\$1157$ and frequency $20$, relative frequency $c=\frac{20}{80}=0.250$.
Step4: Calculate $d$
The cumulative frequency before the row with airfare $\$1053$ is $21$. After adding the frequency of $7$ for $\$1053$, $d=21 + 7=28$.
Step5: Calculate $e$
The cumulative frequency before the row with airfare $\$1205$ is $59$. After adding the frequency of $5$ for $\$1205$, $e=59+5 = 64$.
Step6: Calculate $f$
The cumulative frequency for the row with airfare $\$1079$ is $34$. Relative cumulative frequency $f=\frac{34}{80}=0.425$.
Step7: Calculate $g$
The cumulative frequency for the last row is $80$. Relative cumulative frequency $g=\frac{80}{80}=1.000$.
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$a = 80$, $b = 0.038$, $c = 0.250$, $d = 28$, $e = 64$, $f = 0.425$, $g = 1.000$