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Question
- maria is monitoring the temperature of two substances in her science lab. substance a is currently 96.2° and rising 1.5° each minute. substance b is currently 98.5° and cooling 0.8° each minute. after how many minutes will the two substances be at the same temperature? a. equation: ____
Step1: Set up the equation
Let $x$ be the number of minutes. The temperature of Substance A after $x$ minutes is $96.2 + 1.5x$. The temperature of Substance B after $x$ minutes is $98.5-0.8x$. Set them equal: $96.2 + 1.5x=98.5 - 0.8x$.
Step2: Add $0.8x$ to both sides
$96.2+1.5x + 0.8x=98.5-0.8x+0.8x$, which simplifies to $96.2 + 2.3x=98.5$.
Step3: Subtract 96.2 from both sides
$96.2 + 2.3x-96.2=98.5 - 96.2$, resulting in $2.3x=2.3$.
Step4: Solve for $x$
Divide both sides by 2.3: $x=\frac{2.3}{2.3}=1$.
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a. Equation: $96.2 + 1.5x=98.5 - 0.8x$
The two substances will be at the same temperature after 1 minute.