Question

matching theoretical probability
match the scenario to the probability of it occurring.
spinning blue on a spinner with four different colors in four equal parts
pulling a white marble from a bag of 2 white marbles and 4 red marbles
rolling a 3 on a number cube
flipping a coin to get tails up
1/3
1/6
1/2
1/4

Explanation:

Step1: Analyze Spinner Scenario

Spinner has 4 equal parts, 1 blue. Probability = $\frac{\text{Favorable (blue)}}{\text{Total (4)}} = \frac{1}{4}$.

Step2: Analyze Marble Scenario

Total marbles = 2 (white) + 4 (red) = 6. Favorable (white) = 2. Probability = $\frac{2}{6} = \frac{1}{3}$.

Step3: Analyze Number Cube Scenario

Number cube has 6 faces (1–6). Favorable (rolling 3) = 1. Probability = $\frac{1}{6}$.

Step4: Analyze Coin Flip Scenario

Coin has 2 outcomes (heads/tails). Favorable (tails) = 1. Probability = $\frac{1}{2}$.

Answer:

1. Spinning blue on a spinner with four different colors in four equal parts: $\boldsymbol{\frac{1}{4}}$
2. Pulling a white marble from a bag of 2 white marbles and 4 red marbles: $\boldsymbol{\frac{1}{3}}$ (Wait, correction: Total marbles = 2 + 4 = 6, so probability = $\frac{2}{6}=\frac{1}{3}$? Wait, original problem says "2 white marbles and 4 red marbles"—so total 6. So probability of white is $\frac{2}{6}=\frac{1}{3}$. But let's recheck each:

• Spinner: 4 equal parts, 1 blue. Probability = $\frac{1}{4}$.
• Rolling a 3 on a number cube: A cube has 6 faces (numbers 1–6). Probability = $\frac{1}{6}$.
• Flipping a coin to get tails: 2 outcomes (heads/tails). Probability = $\frac{1}{2}$.
• Pulling white marble: 2 white, 4 red → total 6. Probability = $\frac{2}{6}=\frac{1}{3}$.

So correct matches:

• Spinning blue: $\frac{1}{4}$
• Pulling white marble: $\frac{1}{3}$
• Rolling a 3: $\frac{1}{6}$
• Flipping tails: $\frac{1}{2}$