Question

mg + 2hcl → mgcl₂ + h₂
the theoretical yield for hydrogen gas
was 2.57 g. the actual captured
hydrogen gas had a mass of 0.44 g.
what is the percent yield for the reaction?
? % yield

Explanation:

Step1: Recall the percent yield formula

The formula for percent yield is $\text{Percent Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\%$.

Step2: Identify actual and theoretical yields

Actual yield of $\ce{H_2}$ is $0.44\ \text{g}$, theoretical yield is $2.57\ \text{g}$.

Step3: Substitute values into the formula

$\text{Percent Yield} = \frac{0.44\ \text{g}}{2.57\ \text{g}} \times 100\%$.

Step4: Calculate the value

First, calculate $\frac{0.44}{2.57} \approx 0.1712$. Then multiply by $100\%$: $0.1712 \times 100\% = 17.12\%$.

Answer:

17.1 (or 17.12, depending on rounding)