Question

molar mass of ionic compounds
16 s 32.07
47 ag 107.88
what is the molar mass of the ionic compound ag2s?
ag2s = ? $\frac{g}{mol}$

Explanation:

Step1: Determine molar - mass contribution of Ag

There are 2 Ag atoms in Ag₂S. Molar mass of Ag is 107.88 g/mol, so contribution of Ag is $2\times107.88$ g/mol.
$2\times107.88 = 215.76$ g/mol

Step2: Determine molar - mass contribution of S

There is 1 S atom in Ag₂S. Molar mass of S is 32.07 g/mol.

Step3: Calculate molar mass of Ag₂S

Add the contributions of Ag and S.
$215.76+32.07=247.83$ g/mol

Answer:

$247.83$