Question

1. a motorcycle engine converts 470,000 j of chemical energy into 76,000 j of kinetic energy. how efficient is the engine? round to the nearest percent. 17% 16% 25% 15%

Explanation:

Step1: Recall efficiency formula

Efficiency $\eta=\frac{\text{useful output energy}}{\text{input energy}}\times100\%$

Step2: Identify input and output energy

Input energy $E_{in}=470000\ J$, useful output energy $E_{out} = 76000\ J$

Step3: Calculate efficiency

$\eta=\frac{76000}{470000}\times 100\%$
$=\frac{7600000}{470000}\%$
$\approx 16\%$

Answer:

16%