Question

mr. phan fills a portion of his pool with water on monday. then on tuesday, he fills the pool with water coming from a hose at a constant rate. the table shows the number of feet of water in the pool as a function of time on tuesday.
time on tues. after 9 am(hr) | amount of water in pool(ft)
0 | 1.1
1 | 1.7
2 | 2.3
what is the rate of change of the function?
____ feet per hour.

Explanation:

Step1: Calculate rate between 0-1 hr

Rate = $\frac{1.7 - 1.1}{1 - 0} = 0.6$

Step2: Verify rate between 1-2 hr

Rate = $\frac{2.3 - 1.7}{2 - 1} = 0.6$

Answer:

0.6 feet per hour.