Question

multiple - choice question based on coulombs law, which would you expect to be stronger, the attraction between na+1 and cl - 1 ions or the attraction between mg+2 and s - 2 ions? mgs nacl

Explanation:

Step1: Recall Coulomb's law

$F = k\frac{q_1q_2}{r^2}$, where $F$ is the electrostatic - force, $k$ is a constant, $q_1$ and $q_2$ are the charges of the two ions, and $r$ is the distance between them.

Step2: Calculate the product of charges for NaCl

For $Na^+$ and $Cl^-$, $q_1 = 1$, $q_2=- 1$, so $|q_1q_2| = 1$.

Step3: Calculate the product of charges for MgS

For $Mg^{2 + }$ and $S^{2 - }$, $q_1 = 2$, $q_2=-2$, so $|q_1q_2| = 4$.

Step4: Compare the forces

Since the force is directly proportional to the product of the charges (assuming similar inter - ionic distances), the attraction between $Mg^{2+}$ and $S^{2 - }$ (in MgS) is stronger.

Answer:

MgS