Question

name jayden colemun period 2 date 4/11/25 isotopes, ions, and atoms worksheet atomic # = # of protons. mass # = atomic # + neutrons. protons = electrons when charge is zero.

atomic #	mass #	# p⁺	# e⁻	# n⁰	charge	symbol
2)	180		71	109
3)		40	38	46
4) 92	238		86
5)						$_{82}^{206}$pb⁴⁺
6)		34		45	-2
7)	113	48	49
8) 21	42				0
9)						$_{15}^{31}$p³⁻
10)		83	80	126
11)						$_{47}^{108}$ag
12)	116	49			+3
13)	128	53			-1
14) 76	188		72

Answer:

Let's solve each row step by step using the given formulas: \( \text{Atomic \#} = \# \text{ of protons} \), \( \text{Mass \#} = \text{Atomic \#} + \text{neutrons} \), and \( \text{Protons} = \text{electrons} \) when charge is zero (otherwise, \( \text{Charge} = \text{Protons} - \text{Electrons} \)).

Row 1:

• Atomic \# = 17, so \( \# p^+ = 17 \).
• Charge = 0, so \( \# e^- = \# p^+ = 17 \).
• Mass \# = Atomic \# + \( \# n^0 = 17 + 19 = 36 \).
• Symbol: Atomic \# 17 is Cl, so \( ^{36}_{17}\text{Cl} \).

Row 2:

• \( \# p^+ = \# e^- = 71 \) (charge unknown, but \( \# p^+ = \) Atomic \# = 71).
• Mass \# = 180, so \( \# n^0 = 180 - 71 = 109 \) (matches).
• Charge = \( \# p^+ - \# e^- = 71 - 71 = 0 \).
• Symbol: Atomic \# 71 is Lu, so \( ^{180}_{71}\text{Lu} \).

Row 3:

• \( \# p^+ = 40 \), so Atomic \# = 40.
• \( \# e^- = 38 \), so Charge = \( 40 - 38 = +2 \).
• Mass \# = 40 + 46 = 86.
• Symbol: Atomic \# 40 is Zr, so \( ^{86}_{40}\text{Zr}^{2+} \).

Row 4:

• Atomic \# = 92, so \( \# p^+ = 92 \).
• \( \# e^- = 86 \), so Charge = \( 92 - 86 = +6 \).
• \( \# n^0 = 238 - 92 = 146 \).
• Symbol: Atomic \# 92 is U, so \( ^{238}_{92}\text{U}^{6+} \).

Row 5:

• Symbol \( \ce{^{206}_{82}Pb^{4+}} \): Atomic \# = 82, so \( \# p^+ = 82 \).
• Charge = +4, so \( \# e^- = 82 - 4 = 78 \).
• Mass \# = 206, so \( \# n^0 = 206 - 82 = 124 \).

Row 6:

• \( \# p^+ = 34 \), so Atomic \# = 34.
• Charge = -2, so \( \# e^- = 34 + 2 = 36 \).
• Mass \# = 34 + 45 = 79.
• Symbol: Atomic \# 34 is Se, so \( ^{79}_{34}\text{Se}^{2-} \).

Row 7:

• \( \# p^+ = 48 \), so Atomic \# = 48.
• \( \# e^- = 49 \), so Charge = \( 48 - 49 = -1 \).
• \( \# n^0 = 113 - 48 = 65 \).
• Symbol: Atomic \# 48 is Cd, so \( ^{113}_{48}\text{Cd}^{-} \).

Row 8:

• Atomic \# = 21, so \( \# p^+ = 21 \).
• Charge = 0, so \( \# e^- = 21 \).
• \( \# n^0 = 42 - 21 = 21 \).
• Symbol: Atomic \# 21 is Sc, so \( ^{42}_{21}\text{Sc} \).

Row 9:

• Symbol \( \ce{^{31}_{15}P^{3-}} \): Atomic \# = 15, so \( \# p^+ = 15 \).
• Charge = -3, so \( \# e^- = 15 + 3 = 18 \).
• Mass \# = 31, so \( \# n^0 = 31 - 15 = 16 \).

Row 10:

• \( \# p^+ = 83 \), so Atomic \# = 83.
• \( \# e^- = 80 \), so Charge = \( 83 - 80 = +3 \).
• Mass \# = 83 + 126 = 209.
• Symbol: Atomic \# 83 is Bi, so \( ^{209}_{83}\text{Bi}^{3+} \).

Row 11:

• Symbol \( \ce{^{108}_{47}Ag} \): Atomic \# = 47, so \( \# p^+ = 47 \).
• Charge = 0, so \( \# e^- = 47 \).
• \( \# n^0 = 108 - 47 = 61 \).
• Mass \# = 108.

Row 12:

• \( \# p^+ = 49 \), so Atomic \# = 49.
• Charge = +3, so \( \# e^- = 49 - 3 = 46 \).
• \( \# n^0 = 116 - 49 = 67 \).
• Symbol: Atomic \# 49 is In, so \( ^{116}_{49}\text{In}^{3+} \).

Row 13:

• \( \# p^+ = 53 \), so Atomic \# = 53.
• Charge = -1, so \( \# e^- = 53 + 1 = 54 \).
• \( \# n^0 = 128 - 53 = 75 \).
• Symbol: Atomic \# 53 is I, so \( ^{128}_{53}\text{I}^{-} \).

Row 14:

• Atomic \# = 76, so \( \# p^+ = 76 \).
• \( \# e^- = 72 \), so Charge = \( 76 - 72 = +4 \).
• \( \# n^0 = 188 - 76 = 112 \).
• Symbol: Atomic \# 76 is Os, so \( ^{188}_{76}\text{Os}^{4+} \).

Final Table (Filled):

Row	Atomic #	Mass #	# p⁺	# e⁻	# n⁰	Charge	Symbol
2	71	180	71	71	109	0	\( ^{180}_{71}\text{Lu} \)
3	40	86	40	38	46	+2	\( ^{86}_{40}\text{Zr}^{2+} \)
4	92	238	92	86	146	+6	\( ^{238}_{92}\text{U}^{6+} \)
5	82	206	82	78	124	+4	\( \ce{^{206}_{82}Pb^{4+}} \)
6	34	79	34	36	45	-2	\( ^{79}_{34}\text{Se}^{2-} \)
7	48	113	48	49	65	-1	\( ^{113}_{48}\text{Cd}^{-} \)
8	21	42	21	21	21	0	\( ^{42}_{21}\text{Sc} \)
9	15	31	15	18	16	-3	\( \ce{^{31}_{15}P^{3-}} \)
10	83	209	83	80	126	+3	\( ^{209}_{83}\text{Bi}^{3+} \)
11	47	108	47	47	61	0	\( \ce{^{108}_{47}Ag} \)
12	49	116	49	46	67	+3	\( ^{116}_{49}\text{In}^{3+} \)
13	53	128	53	54	75	-1	\( ^{128}_{53}\text{I}^{-} \)
14	76	188	76	72	112	+4	\( ^{188}_{76}\text{Os}^{4+} \)

(Note: For each row, the filled values follow the formulas for atomic number, mass number, protons, electrons, neutrons, charge, and symbol.)