Question

1 the net force is 7.00 newtons, and the acceleration is 9.33 meters/second² select the correct answer. reset what is the net force and acceleration of a ball of mass 0.750 kilograms that is subjected to forces of 11.00 newtons and 7.00 newtons from opposite directions? a. the net force is 4.00 newtons, and the acceleration is 5.33 meters/second². b. the net force is 4.00 newtons, and the acceleration is 9.33 meters/second². c. the net force is 7.00 newtons, and the acceleration is 9.33 meters/second². d. the net force is 11.00 newtons, and the acceleration is 14.0 meters/second² next

Explanation:

Step1: Calculate net force

The two forces are in opposite directions. Net force $F_{net}=F_1 - F_2$. Here, $F_1 = 11.00$ N and $F_2=7.00$ N. So, $F_{net}=11.00 - 7.00=4.00$ N.

Step2: Calculate acceleration

According to Newton's second - law $F = ma$, where $F = F_{net}$, $m = 0.750$ kg and $a$ is the acceleration. We can solve for $a$: $a=\frac{F_{net}}{m}$. Substitute $F_{net}=4.00$ N and $m = 0.750$ kg into the formula, $a=\frac{4.00}{0.750}\approx5.33$ m/s².

Answer:

A. The net force is 4.00 newtons, and the acceleration is 5.33 meters/second²