Question

park 150 ft, map 1 in. write a proportion using the variable f. then solve for f using means and extremes. write a proportion using the variable s. then solve for s using means and extremes. enter the actual distance, s, from the swimming pool to the skating rink. enter the actual distance, f, from sunny grove to the swimming pool.

Explanation:

Step1: Set up the proportion

The scale is 1 in. : 150 ft. So the proportion for the first - part (from Sunny Grove to the swimming pool) is $\frac{1}{150}=\frac{3.3}{f}$, where $f$ is the actual distance in feet.

Step2: Cross - multiply

Cross - multiplying gives us $1\times f = 150\times3.3$.

Step3: Solve for $f$

$f=150\times3.3 = 495$ ft.
For the second part, the proportion is $\frac{1}{150}=\frac{1}{s}$, where $s$ is the actual distance in feet. Cross - multiplying gives $1\times s=150\times1$, so $s = 150$ ft.

Answer:

The actual distance $f$ from the swimming pool to the skating rink is 495 ft and the actual distance $s$ from Sunny Grove to the swimming pool is 150 ft.