Question

part 1 of 4
identify the precipitate formed in each of the following reactions. if no precipitate is formed, enter none.
note: reference the solubility of ionic compounds in water table for additional information.
the brown precipitate formed in the reaction between naoh and $\text{fecl}_3$ is $square$.
none

Explanation:

Step1: Write the double displacement reaction

$\text{3NaOH}(aq) + \text{FeCl}_3(aq)
ightarrow \text{3NaCl}(aq) + \text{Fe(OH)}_3(s)$

Step2: Identify insoluble product

Based on solubility rules, hydroxides of transition metals like iron(III) are insoluble in water, forming a brown precipitate, while sodium chloride is soluble.

Answer:

$\text{Fe(OH)}_3$ (Iron(III) hydroxide)