Question

part 2
refer to the figures below to answer the following questions.

1. using any 3 metals from the table, you made some

cubes that are 2.00 cm on every side.

a. calculate the volume of each cube in cm³ and in
ml? (show your thinking & work below)
v = ____ cm³ v = ____ ml

b. what is density ?
the equation for density is ______

c. using the volume from part a and information from the table, find the mass of
these metal cubes: (show your work below)
lead cube ______
nickel cube ______
zinc cube ______

1. a student filled a graduated cylinder with water and read the meniscus at 25.8 ml. the

student then dropped a solid material into the graduated cylinder and the water level rose to
35.9 ml. if the solid material had a density of 2.99 g/ml, determine the mass of the solid
object.

(table: substance | density (g/ml)
aluminum | 2.70
titanium | 4.54
zinc | 7.13
tin | 7.31
iron | 7.87
nickel | 8.90
copper | 8.96
silver | 10.50
lead | 13.55
mercury | 19.30
gold | 19.30)

Explanation:

3a

Step1: Calculate volume of cube

The formula for the volume \( V \) of a cube is \( V = s^3 \), where \( s \) is the length of a side. Here, \( s = 2.00 \, \text{cm} \).
\[
V = (2.00 \, \text{cm})^3 = 8.00 \, \text{cm}^3
\]

Step2: Convert volume to mL

Since \( 1 \, \text{cm}^3 = 1 \, \text{mL} \), the volume in mL is the same as in \( \text{cm}^3 \). So \( V = 8.00 \, \text{mL} \).

Density is the mass of a substance per unit volume. The formula for density (\(
ho \)) is the ratio of mass (\( m \)) to volume (\( V \)).

Step1: Recall density formula

Density \(
ho = \frac{m}{V} \), so rearranged for mass \( m =
ho \times V \).
Density of lead (\(
ho_{\text{lead}} \)) = \( 13.55 \, \text{g/mL} \), volume \( V = 8.00 \, \text{mL} \).

Step2: Calculate mass

\[
m_{\text{lead}} = 13.55 \, \text{g/mL} \times 8.00 \, \text{mL} = 108.4 \, \text{g}
\]

Answer:

\( V = \boldsymbol{8.00} \, \text{cm}^3 \)
\( V = \boldsymbol{8.00} \, \text{mL} \)

3b