QUESTION IMAGE
Question
- in a particular sequence, you multiply the term number by 6 and subtract 3, to determine a particular term.
a) determine the sixth term.
b) which term is 63?
Step1: Define the sequence formula
Let $n$ = term number, term value $a_n = 6n - 3$
Step2: Calculate 6th term (part a)
Substitute $n=6$ into formula:
$a_6 = 6(6) - 3$
$a_6 = 36 - 3 = 33$
Step3: Solve for $n$ when $a_n=63$ (part b)
Set $6n - 3 = 63$, solve for $n$:
$6n = 63 + 3 = 66$
$n = \frac{66}{6} = 11$
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a) 33
b) 11th term