Question

pineapple $1\frac{3}{4}$
strawberry $1\frac{1}{8}$
mango $1$
corn $1\frac{7}{8}$
lettuce $1\frac{1}{2}$
use the data in the table to complete the line plot below.
click to select the x’s. to clear a column, click on the number line below it.
amount of smoothie
line plot with x’s and number line: $1$, $1\frac{1}{8}$, $1\frac{1}{4}$, $1\frac{3}{8}$, $1\frac{1}{2}$, $1\frac{5}{8}$, $1\frac{3}{4}$, $1\frac{7}{8}$ (labeled cups)

Explanation:

Step1: Identify each data point

First, we list out the amounts from the table: Pineapple: \(1\frac{3}{4}\), Strawberry: \(1\frac{1}{8}\), Mango: \(1\), Corn: \(1\frac{7}{8}\), Lettuce: \(1\frac{1}{2}\).

Step2: Convert to eighths for easier plotting (optional, but helps)

• \(1 = \frac{8}{8}\)
• \(1\frac{1}{8}=\frac{9}{8}\)
• \(1\frac{1}{2}=\frac{12}{8}=1\frac{4}{8}\) (wait, actually, to match the number line, let's convert to eighths properly:
• \(1 = 1\frac{0}{8}\)
• \(1\frac{1}{8}=1\frac{1}{8}\)
• \(1\frac{1}{2}=1\frac{4}{8}\) (since \(\frac{1}{2}=\frac{4}{8}\))
• \(1\frac{3}{4}=1\frac{6}{8}\) (since \(\frac{3}{4}=\frac{6}{8}\))
• \(1\frac{7}{8}=1\frac{7}{8}\)

Step3: Plot each X

• For Mango (\(1\)): Place an X above \(1\) on the number line.
• For Strawberry (\(1\frac{1}{8}\)): Place an X above \(1\frac{1}{8}\).
• For Lettuce (\(1\frac{1}{2}=1\frac{4}{8}\)): Wait, the number line has \(1\frac{1}{2}\) as a mark? Wait, looking at the number line: the marks are \(1\), \(1\frac{1}{8}\), \(1\frac{1}{4}\) (\(1\frac{2}{8}\)), \(1\frac{3}{8}\), \(1\frac{1}{2}\) (\(1\frac{4}{8}\)), \(1\frac{5}{8}\), \(1\frac{3}{4}\) (\(1\frac{6}{8}\)), \(1\frac{7}{8}\).
• So Lettuce is \(1\frac{1}{2}\), so X above \(1\frac{1}{2}\).
• Pineapple is \(1\frac{3}{4}=1\frac{6}{8}\), so X above \(1\frac{3}{4}\).
• Corn is \(1\frac{7}{8}\), so X above \(1\frac{7}{8}\).

So the number of X's per mark:

• \(1\): 1 X (Mango)
• \(1\frac{1}{8}\): 1 X (Strawberry)
• \(1\frac{1}{2}\): 1 X (Lettuce)
• \(1\frac{3}{4}\): 1 X (Pineapple)
• \(1\frac{7}{8}\): 1 X (Corn)
• The other marks (\(1\frac{1}{4}\), \(1\frac{3}{8}\), \(1\frac{5}{8}\)) have 0 X's initially (but we only plot the ones from the data).

Answer:

To complete the line plot:

• Above \(1\): 1 X (for Mango)
• Above \(1\frac{1}{8}\): 1 X (for Strawberry)
• Above \(1\frac{1}{2}\): 1 X (for Lettuce)
• Above \(1\frac{3}{4}\): 1 X (for Pineapple)
• Above \(1\frac{7}{8}\): 1 X (for Corn)

(Note: Since the problem is about plotting, the final answer is the correct placement of X's as described. If we were to represent the counts: \(1\):1, \(1\frac{1}{8}\):1, \(1\frac{1}{2}\):1, \(1\frac{3}{4}\):1, \(1\frac{7}{8}\):1, and 0 for the others.)