Question

1. please identify each element associated with the orbital notation or electron configuration. note: one \slash\ is one electron, two \slashes\ are two electrons. a) $1s^2 2s^2$ b) $1s^2 2s^2 2p^5$ c) $1s^2 2s^2 2p^6 3s^1$ d) (orbital diagram: 1s with two slashes, 2s with two slashes, 2p with three orbitals each with two slashes, 3s with one slash)

Explanation:

Part (a)

Step1: Calculate total electrons

To find the element, we first calculate the total number of electrons from the electron configuration \(1s^2 2s^2\). The sum of the exponents gives the total number of electrons. So, \(2 + 2=4\).

Step2: Identify the element

The atomic number of an element is equal to the number of electrons in a neutral atom. So, the element with atomic number 4 is Beryllium (Be).

Step1: Calculate total electrons

For the electron configuration \(1s^2 2s^2 2p^5\), we sum the exponents: \(2+2 + 5=9\).

Step2: Identify the element

The element with atomic number 9 is Fluorine (F).

Step1: Calculate total electrons

From the electron configuration \(1s^2 2s^2 2p^6 3s^1\), we sum the exponents: \(2+2+6 + 1 = 11\).

Step2: Identify the element

The element with atomic number 11 is Sodium (Na).

Answer:

Beryllium (Be)

Part (b)