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3. $\frac{1}{2}$ pound in 5 days (x) independent: _______________ (y) d…

Question

  1. $\frac{1}{2}$ pound in 5 days

(x) independent: _______________
(y) dependent:_______________
$\frac{y}{x}$ unit rate: _______________

Explanation:

Step1: Identify independent variable

The independent variable is the input that is not affected by the other quantity; here, it is time (days).

Step2: Identify dependent variable

The dependent variable depends on the independent variable; here, it is the amount of pounds, as it depends on the number of days.

Step3: Calculate unit rate

Unit rate is $\frac{y}{x}$, where $y$ is pounds and $x$ is days. Substitute $y=\frac{1}{2}$ and $x=5$:
$\text{Unit rate} = \frac{\frac{1}{2}}{5} = \frac{1}{2} \times \frac{1}{5} = \frac{1}{10}$

Answer:

(x) Independent: Days
(y) Dependent: Pounds
$\frac{y}{x}$ Unit rate: $\frac{1}{10}$ pound per day