Question

practice atom diagrams: fill in the missing information and draw the
element helium
electrons:
protons: 2
neutrons:
mass 3 amu
charge 0 (neutral atom)

element
electrons:
protons: 6
neutrons:
mass 11 amu
charge 0 (neutral atom)

element
electrons:
protons: 9
neutrons: 8
mass amu
charge 0 (neutral atom)

Explanation:

Step1: Recall atomic - structure relationships

In a neutral atom, the number of electrons equals the number of protons. The mass number is the sum of protons and neutrons.

Step2: Solve for the first atom (Helium)

Since the number of protons is 2 and it's a neutral atom, the number of electrons is 2. Using the formula $Mass\ number=Protons + Neutrons$, we can find the number of neutrons. Given mass number = 3 amu and protons = 2, then $Neutrons=Mass\ number - Protons=3 - 2 = 1$.

Step3: Solve for the second atom

The number of protons is 6 and it's a neutral atom, so the number of electrons is 6. Using $Mass\ number=Protons + Neutrons$, with mass number = 11 amu and protons = 6, we get $Neutrons=11 - 6 = 5$. The element with 6 protons is Carbon.

Step4: Solve for the third atom

Since it's a neutral atom with 9 protons, the number of electrons is 9. Using $Mass\ number=Protons + Neutrons$, with protons = 9 and neutrons = 8, the mass number is $9 + 8=17$ amu. The element with 9 protons is Fluorine.

Answer:

Element	Helium	Carbon	Fluorine
Protons:	2	6	9
Neutrons:	1	5	8
Mass	3 amu	11 amu	17 amu
Charge	0 (Neutral Atom)	0 (Neutral Atom)	0 (Neutral Atom)