QUESTION IMAGE
Question
practice: balancing equations #2
show all work on a separate sheet of paper. place coefficient final answers in the blanks provided. you can leave coefficients of \1\ blank. for #14 and 15, you must write out the equation for the reaction first.
- n₂ + h₂ → nh₃
- kclo₃ → kcl + o₂
- nacl + f₂ → naf + cl₂
- h₂ + o₂ → h₂o
- pb(oh)₂ + hcl → h₂o + pbcl₂
- albr₃ + k₂so₄ → kbr + al₂(so₄)₃
- ch₄ + o₂ → co₂ + h₂o
- c₃h₈ + o₂ → co₂ + h₂o
- fecl₃ + naoh → fe(oh)₃ + nacl
- p + o₂ → p₂o₅
- co₂ + h₂o → c₆h₁₂o₆ + o₂
- s₈ + o₂ → so₃
- mn + hi → h₂ + mni₃
- when crystallized c₆h₁₂o₆ is burned in oxygen gas (o₂), carbon dioxide and water vapor are formed.
- if a copper coil is placed into a solution of dissolved silver (i) nitrate, silver crystals will form. also, aqueous copper (i) nitrate is made.
reactions unit
Step1: Balance equation 13
For the reaction $Mn + HI
ightarrow H_2+MnI_2$, first balance iodine. Since there are 2 iodines in $MnI_2$, we need 2 moles of $HI$. Then, to balance hydrogen, we have 2 hydrogens in $H_2$ and 2 in $2HI$, and 1 mole of $Mn$ on both sides. So the balanced equation is $1Mn + 2HI
ightarrow1H_2 + 1MnI_2$.
Step2: Balance equation 14
The reaction for the burning of $C_6H_{12}O_6$ in oxygen is $C_6H_{12}O_6+6O_2
ightarrow6CO_2 + 6H_2O$. First, balance carbon. There are 6 carbons in $C_6H_{12}O_6$, so we get $6CO_2$. Then balance hydrogen. There are 12 hydrogens in $C_6H_{12}O_6$, so we get $6H_2O$. Finally, count the oxygens. On the left - hand side, we have 6 from $C_6H_{12}O_6$ and 12 from $6O_2$ (total 18), and on the right - hand side, we have 12 from $6CO_2$ and 6 from $6H_2O$ (total 18).
Step3: Balance equation 15
The reaction of copper with silver nitrate is $Cu + 2AgNO_3
ightarrow2Ag+Cu(NO_3)_2$. First, balance silver. Since there are 2 silver atoms in $2AgNO_3$, we get 2 moles of $Ag$. Then, copper and nitrate ions are also balanced with 1 mole of $Cu$ and 2 moles of nitrate ions on both sides.
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- $1Mn + 2HI
ightarrow1H_2 + 1MnI_2$
- $C_6H_{12}O_6+6O_2
ightarrow6CO_2 + 6H_2O$
- $Cu + 2AgNO_3
ightarrow2Ag+Cu(NO_3)_2$