Question

pre - laboratory assignment 2
name:____ section:__ date:____
beverage density lab

1. if the following mass and volume data are used to calculate the density of solution, how many significant figures are allowed in the calculated density? mass of solution = 12.53 g, volume of solution = 8.27 ml.
2. calculate the density of the solution described in question 1.

Explanation:

Step1: Recall significant - figure rules for division

When dividing two measured values, the result should have the same number of significant figures as the measured value with the fewest significant figures.
The mass $m = 12.53\ g$ has 4 significant figures, and the volume $V=8.27\ mL$ has 3 significant figures.

Step2: Determine significant figures in density

Since the volume has 3 significant figures (the fewest between the mass and volume values), the calculated density will have 3 significant figures.

Step3: Calculate density

The formula for density is $
ho=\frac{m}{V}$. Substitute $m = 12.53\ g$ and $V = 8.27\ mL$ into the formula: $
ho=\frac{12.53}{8.27}\ g/mL$.
$
ho=\frac{12.53}{8.27}\approx1.5272\ g/mL$. Rounding to 3 significant figures, $
ho = 1.53\ g/mL$.

Answer:

1. 3
2. $1.53\ g/mL$