Question

1. predict the products of the following reactions. identify the precipitate and the spectator ions and write the net ionic equation.

chemical reactions	precipitate	spectator ions	net ionic equation
b.) k₃po₄(aq) + zn(ch₃coo)₂(aq) →<br>__ + __
c.) na₂s(aq) + pb(no₃)₂(aq) →<br>__ + __

Explanation:

Step1: Write balanced molecular equations

a. $AgNO_3(aq)+NaBr(aq)
ightarrow AgBr(s)+NaNO_3(aq)$
b. $2K_3PO_4(aq)+3Zn(CH_3COO)_2(aq)
ightarrow Zn_3(PO_4)_2(s)+6KCH_3COO(aq)$
c. $Na_2S(aq)+Pb(NO_3)_2(aq)
ightarrow PbS(s)+2NaNO_3(aq)$

Step2: Write total ionic equations

a. $Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Br^-(aq)
ightarrow AgBr(s)+Na^+(aq)+NO_3^-(aq)$
b. $6K^+(aq)+2PO_4^{3 -}(aq)+3Zn^{2+}(aq)+6CH_3COO^-(aq)
ightarrow Zn_3(PO_4)_2(s)+6K^+(aq)+6CH_3COO^-(aq)$
c. $2Na^+(aq)+S^{2 -}(aq)+Pb^{2+}(aq)+2NO_3^-(aq)
ightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)$

Step3: Identify spectator ions

a. Spectator ions are $Na^+$ and $NO_3^-$
b. Spectator ions are $K^+$ and $CH_3COO^-$
c. Spectator ions are $Na^+$ and $NO_3^-$

Step4: Write net - ionic equations

a. $Ag^+(aq)+Br^-(aq)
ightarrow AgBr(s)$
b. $3Zn^{2+}(aq)+2PO_4^{3 -}(aq)
ightarrow Zn_3(PO_4)_2(s)$
c. $Pb^{2+}(aq)+S^{2 -}(aq)
ightarrow PbS(s)$

Answer:

Chemical Reactions	Precipitate	Spectator Ions	Net Ionic Equation

| a. $AgNO_3(aq)+NaBr(aq)
ightarrow$ | $AgBr$ | $Na^+,NO_3^-$ | $Ag^+(aq)+Br^-(aq)
ightarrow AgBr(s)$ |
| b. $K_3PO_4(aq)+Zn(CH_3COO)_2(aq)
ightarrow$ | $Zn_3(PO_4)_2$ | $K^+,CH_3COO^-$ | $3Zn^{2+}(aq)+2PO_4^{3 -}(aq)
ightarrow Zn_3(PO_4)_2(s)$ |
| c. $Na_2S(aq)+Pb(NO_3)_2(aq)
ightarrow$ | $PbS$ | $Na^+,NO_3^-$ | $Pb^{2+}(aq)+S^{2 -}(aq)
ightarrow PbS(s)$ |