Question

1. if a projectile flies north 387 meters in 5.8 seconds, what is its velocity? 9. calculate the velocity of a mountain climber if that climber is moving northeast at a pace of 1.6 km in 1.4 hours?

Explanation:

Step1: Recall velocity formula

Velocity $v=\frac{d}{t}$, where $d$ is distance and $t$ is time.

Step2: Solve for the projectile

For the projectile, $d = 387$ meters and $t=5.8$ seconds. So $v_1=\frac{387}{5.8}\approx66.72$ m/s north.

Step3: Convert units for the climber

The climber's distance $d = 1.6$ km = 1600 m and time $t = 1.4$ hours = $1.4\times3600 = 5040$ s.

Step4: Solve for the climber

Using the velocity formula, $v_2=\frac{1600}{5040}\approx0.32$ m/s northeast.

Answer:

The velocity of the projectile is approximately 66.72 m/s north and the velocity of the mountain - climber is approximately 0.32 m/s northeast.